i\hbar \frac{\partial}{\partial t} \left|\Psi(t)\right>=H\left|\Psi(t)\right>

$$i\hbar \frac{\partial}{\partial t} \left|\Psi(t)\right>=H\left|\Psi(t)\right>$$

$i\hbar \frac{\partial}{\partial t} \left|\Psi(t)\right>=H\left|\Psi(t)\right>$

$G_{\mu\nu} = T_{\mu\nu}$